One example is not enough for you to be able to understand and to solve the currents and voltages of a specific circuit. So in this page, we will try our best to give examples and explain it in a way everybody can understand. So let the solving begins.
Example 1:
Determine the currents and voltages in the circuit below.
Determine the currents and voltages in the circuit below.
Hmm it seems like there are lots of hidden given (treasures) in the given circuit but don't worry we will solve it piece by piece.
Okay, first thing you need to do is to look for v1 but wait, where's v1? And where's v2? And the rest? Oh no we're doomed! No just kidding. (That's our first impression after seeing that circuit heheh)
Okay, first thing you need to do is to look for v1 but wait, where's v1? And where's v2? And the rest? Oh no we're doomed! No just kidding. (That's our first impression after seeing that circuit heheh)
Have you wondering what's the purpose of 0.75A and 0.25A? Since it is connected in a common node, we can sum it up.
i= 0.75A + 0.25A
i = 1A
So we have now our first current which is 1A we can use that to solve for the v1
at .
v1 = 1A (20Ω )
v1 = 20V
i= 0.75A + 0.25A
i = 1A
So we have now our first current which is 1A we can use that to solve for the v1
at .
v1 = 1A (20Ω )
v1 = 20V
So now we solved the values of i1and v1 where going to solve for the v2 on the resistor. We can use KCL to solve for the current through resistor 10Ω
i2 + i1 - 0.25A = 0
i2 + i1 = 0.25
i2 = 0.25 – 1
(i2 = -0.75 A) –
i2 = 0.75A
Now we will be solving for v3:
We can use KVL to solve for v3,
15 – V3 = 0
15 = v3
Solving now for the i3 at 60Ω resistor,
V3 = i3 (R)
i3 = 60Ω/ 15V
i3 = 0.25A
i2 + i1 - 0.25A = 0
i2 + i1 = 0.25
i2 = 0.25 – 1
(i2 = -0.75 A) –
i2 = 0.75A
Now we will be solving for v3:
We can use KVL to solve for v3,
15 – V3 = 0
15 = v3
Solving now for the i3 at 60Ω resistor,
V3 = i3 (R)
i3 = 60Ω/ 15V
i3 = 0.25A
Example 2:
Determine I1 and vs if the current through the 3Ω resistor = 2A
Determine I1 and vs if the current through the 3Ω resistor = 2A
The first thing we need to solve is the Req of 3Ω and 6Ω.
Since 3Ω and 6Ω are parallel, the voltage across it is same to the 3Ω and 6Ω. Using Ohm's law and the given 2A current through the 3Ω resistor and the current through 6Ω resistor
Solving for the i3 and the total Req...
Now, we will be solving for Vs and I
Example 3
Determine Rab
A quite complicated circuit but not really.
First thing we need to do is to analyze the circuit (of course) and look for an open and a short circuit in the circuit.
First thing we need to do is to analyze the circuit (of course) and look for an open and a short circuit in the circuit.
Since the part of the circuit that is highlighted above is I = 0A, it means that the current on each of its resistor has 0 current. If there is no current, there is no resistance, voltage is equals to E.
The circuit below shows that the (diamond) resistors at the top of our circuit are rearrange into a parallel connection. Using the current division we will be able to solve the equivalent resistances of the two parallel connections. After solving the parallel resistor equivalent convert it to a series connection as shown in the circuit below and you can directly sum up all the resistors in the circuit to get Rab.
The circuit below shows that the (diamond) resistors at the top of our circuit are rearrange into a parallel connection. Using the current division we will be able to solve the equivalent resistances of the two parallel connections. After solving the parallel resistor equivalent convert it to a series connection as shown in the circuit below and you can directly sum up all the resistors in the circuit to get Rab.